X+3y=3

2x-4y=6

solve the equations

So divide the second equation by 2

x-2y=3

the first equation is

x+3y=3

subsitute

3=3 so therefor

x-2y=x+3y

subtract x from both sides

-2y=3y

add 2y to both sides

0=5y

ofviously y=0 so subsitute

x-2y=3

x - (2) 0=3

x-0=3

x=3

x=3

y=0

Subtract the second equation from double the first equation:

2x+6y-2x - (-4y) = 0

10y=0

Therefore, y=0. Substituting this into the first equation, we see that:

x+3 (0) = 3

x=3

Therefore, x=3. The solution to this system is x=3, y=0, or (3, 0).