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16 December, 23:58

Which is the center of a circle whose equation is x2+y2+4x-8y+11=0?

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  1. 17 December, 00:11
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    Center (-2, 4)

    Step-by-step explanation:

    x^2 + 4x + y^2 - 8y = - 11

    (x^2 + 4x + (4/2) ^2 + (y^2 - 8y + (8/2) ^2) = - 11 + 4 + 16

    (x + 2) ^2 + (y - 4) ^2 = 9

    Center (-2, 4)
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