A ball is thrown from a height of 44 meters with an initial downward velocity of 6 m/s. The ball's height h (in meters) after t seconds is given by the following. h = 44-6t-5t^2

How long after the ball is thrown does it hit the ground?

Round your answer (s) to the nearest hundredth.

(If there is more than one answer, use the "or" button.)

Question

28 May, 08:16

+1

Answers (1)

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Bailee Carrillo · Answer 1

0 = - 5t^2-6t+44

a = - 5 b = - 6 c = 44

Quadratic formula

- - 6 - v 36-4 (-5) (44). / 2 (-5)

6 - v 916/-10

Answer 2.43 seconds