There is a spinner with 9 equal areas, numbered 1 through 9. If the spinner is spun one time, what is the probability that the result is a multiple of 2 and a multiple of 3?

Question

Jay

Mathematics

23 February, 08:09

There is a spinner with 9 equal areas, numbered 1 through 9. If the spinner is spun one time, what is the probability that the result is a multiple of 2 and a multiple of 3?

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Answers (2)

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Pierce Irwin · Answer 1

2/3 = 0.666 = 66.67%

Step-by-step explanation:

No of multiples of 2 = 4

No. of multiples of 3 = 3

6 is common so total unique multiples of 2 and 3 = 4+3-1 = 6

probability = favourable outcomes/total outcomes = 6/9=2/3=0.666

Makayla Pittman · Answer 2

If we think of the numbers 1 through nine, only 1 of those numbers is a multiple of 2 AND 3 and that number is 6.

So, basically, the question is asking what is the probability that "6" will appear. That is a one out of 9 probability or 1/9 or 11.11%