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14 January, 22:30

Find f' (x) for f (x) = - 8x^2 - 5x - 4.

A.) - 16x - 5

B.) - 16x - 4

C.) 16x + 5

D.) None of these

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Answers (1)
  1. 14 January, 22:39
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    D/dx of - 8x^2 - 5x - 4

    So, use the power rule: - 8 * d/dx (x^2) this means (x^n) ' = n * x^n-1

    So - 8*2x

    -5 * d/dx (x) = - 5 * 1

    So - 5

    d/dx of 4 is 0, because 4 is a costant.

    Final result

    -16x - 5
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