The length of a rectangle is four times its width.

If the area of the rectangle is 144 yd^2, find its perimeter.

Question

Nehemiah Cherry

Mathematics

3 May, 21:23

The length of a rectangle is four times its width.

If the area of the rectangle is 144 yd^2, find its perimeter.

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Answers (1)

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Petie · Answer 1

Hello;

x is the length, y the width:

x = 4y ... (1)

xy = 144 ... (2)

subsct in (2) : 4y (y) = 144

y² = 36

y = 6 yd so : x = 24 yd

the perimeter is : 2 (6+24) = 60 yd

The length of a rectangle is four times its width.If the area of the rectangle is 144 yd^2, find its perimeter.

The length of a rectangle is four times its width.

If the area of the rectangle is 144 yd^2, find its perimeter.