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23 February, 03:22

Find the standard form of the equation of the parabola with a focus at (-7, 0) and a directrix at x = 7.

a) x = negative 1 divided by 28y^2

b) - 28y = x^2

c) y^2 = - 14x

d) y = negative 1 divided by 28x^2

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Answers (2)
  1. 23 February, 03:38
    0
    y^2 = - 28x.

    Step-by-step explanation:

    The general form for this type of parabola is y^2 = 4ax where the focus is at (a, 0) and the directrix is x = - a.

    So substituting we get

    y^2 = 4 * - 7 * x

    y^2 = - 28x
  2. 23 February, 03:43
    0
    x = 1 / (4p) * y^2

    x = 1 / (4*-7) * y^2

    x = - 1/28*y^2
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