If c = 1/3 and b=3
then in 3c / (2b^2) or 2b to the power of two. Would you do 2*3=6 (because of b = 3) then 6^2 6x6=36 and then divide it by 3 3/36 or would you do 3 to the power of two which is 9, and then multiply it by 2, and then divide it by 3 so 3/18. I keep mixing it up sorry
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