If 0≤θ≤90 and sin (θ) = p, then which of the following gives the value of tan (θ) ?

1) p/1-p

2) (√ 1-p^2) / p

3) p / (√ 1-p^2)

4) √1-p^2

p/√ (1-p^2)

Step-by-step explanation:

Firstly we can write our sin (θ) = p/1

Mathematically, the sine of an angle refers to the ratio of the opposite to that of the hypotenuse. Hence we can say that p is the opposite while 1 is the hypotenuse of the right-angled triangle.

Now to get the third side of the right angled triangle, we use the pythagoras' theorem. This states that the square of the hypotenuse equals the addition of the squares of the other two sides of the right angled triangle. Thus, mathematically:

1^2 = p^2 + adjacent^2

Adjacent^2 = 1 - p^2

Adjacent = √ (1-p^2)

The tan of an angle refers to the ratio of the opposite to the adjacent.

Thus, our tan here will be p/√ (1-p^2)

Tan θ = p/√ (1-p^2)

3) p / (√ 1-p^2)

Step-by-step explanation:

In trigonometry, the three fundamental or basic functions are represented by the notation SOH CAH TOA where

SOH

Sin θ = opposite/hypotenuse

Cos θ = Adjacent / hypotenuse

Tan θ = Opposite / Adjacent

And from Pythagoras theorem,

Opposite ² + Adjacent ² = Hypotenuse²

Hence if Sin θ = p/1, the opposite side is p, the hypotenuse side is 1 then

the adjacent side from the equation above

Adjacent side² = 1 - p²

Adjacent side = √ (1 - p²)

Tan θ = p/√ (1 - p²)