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14 January, 02:55

A bag contains 6 red balls, 4 green balls, and 3 blue balls. If we choose a ball, then another ball without putting the first one back in the bag, what is the probability that the first ball will be green and the second will be red?

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  1. 14 January, 03:07
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    2/13

    Step-by-step explanation:

    There are 6 + 4 + 3 = 13 balls all together.

    If the first one is green, this will happen with a probability of 4/13. Now there are 12 balls left

    There are 6 red balls. 6/12 = 1/2

    The probability of the way this happens is 1/2 * 4/13 = 2/13
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