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22 January, 21:40

The first two terms of a geometric sequence are a1 = 1/3 and a2 = 1/6. What is a8, the eighth term?

A. 1/384

B. 1/128

C. 1/768

D. 1/256

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Answers (1)
  1. 22 January, 22:03
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    A1=1/3

    a2 = 1/6

    The constant factor is 1/2

    a1=2/3*1/2

    a2=2/3*1/2^2

    So ...

    a8=2/3 * (1/2) ^8

    2/3*1/256

    A. 1/384
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