What is the period and frequency of a 10-pound weight oscillating (as a pendulum) on a 5-meter-long rope?

The mass of the pendulum does not affect the period and frequency

The period can be determined using the formula:

T = 2π √ (L/g)

where L is the length of the rope

and g is the acceleration due to gravity = 9.8 m/s2

Plugging in the values:

T = 2π √ (5/9.8)

T = 10π/7 = 4.49 s

And for the frequency:

f = 1/T

f = 1/4.49

f = 0.22 Hz