A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which expresses the ratio of the volume of the candle to its surface area (including the base) ? for cone, v=1/3pir^2h and sa=pir^2 pir sqrt r^2 h^2.

Question

Kaylie Downs

Mathematics

18 December, 22:41

A candle in the shape of a circular cone has a base of radius r and a height of h that is the same length as the radius. which expresses the ratio of the volume of the candle to its surface area (including the base) ? for cone, v=1/3pir^2h and sa=pir^2 pir sqrt r^2 h^2.

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Answers (2)

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Desmond Livingston · Answer 1

the ratio of the volume of the candle to its surface area is

R = (1/3) pir^2h / pir^2 sqrt (r^2 + h^2) = (1/3) h / sqrt (r^2 + h^2)

and since h=r, (the same length)

R = (1/3) h / sqrt (r^2 + r^2) = (1/3) r / sqrt (2r^2, sqrt (2r^2=r sqrt (2)

the ratio is

R = (1/3) sqrt (2)

Antoine Guerra · Answer 2

Antoine Guerra 18 December, 23:08

0

The answer is r (1-sqrt2) / - 3