Ask Question
28 August, 03:45

Verify (Prove whether true or false)

1/sec^2k=sin^2k*cos^2k+cos^4k

+1
Answers (1)
  1. 28 August, 04:00
    0
    The expression is true.

    Step-by-step explanation:

    Step 1: Prove the expression. 1/sec²k = sin²k cos²k + cos^4k

    Left Hand Side = 1/sec²k = cos²k

    Right Hand Side = sin²k cos²k + cos^4k

    = cos²k (sin²k + cos²k) (Taking cos²k as common)

    = cos²k (∵sin²k + cos²k = 1)

    ⇒ Left Hand Side = Right Hand Side

    So the expression is true.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question 👍 “Verify (Prove whether true or false) 1/sec^2k=sin^2k*cos^2k+cos^4k ...” in 📗 Mathematics if the answers seem to be not correct or there’s no answer. Try a smart search to find answers to similar questions.
Search for Other Answers