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6 November, 18:07

5 squirrels were found to have an average weight of 8.9 ounces with a sample standard deviation is 0.9. Find the 95% confidence interval of the true mean weight.

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  1. 6 November, 19:44
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    Answer: (8.11, 9.69)

    the 95% confidence interval of the true mean weight

    = (8.11, 9.69)

    Step-by-step explanation:

    Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

    The confidence interval of a statistical data can be written as.

    x+/-zr/√n

    Given that;

    Mean x = 8.9

    Standard deviation r = 0.9

    Number of samples n = 5

    Confidence interval = 95%

    z (at 95% confidence) = 1.96

    Substituting the values we have;

    8.9+/-1.96 (0.9/√5)

    8.9+/-1.96 (0.4025)

    8.9+ / - 0.79

    = (8.11, 9.69)

    Therefore at 95% confidence interval (a, b) = (8.11, 9.69)
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