D (1) = 8 d (n) = d (n-1) x (-5) what is the 3rd term in the sequence

With the rule: d (n) = d (n-1) x (-5), we have:

d (1) = 8

d (2) = d (1) x (-5) = 8x (-5) = -40

d (3) = d (2) x (-5) = - 40x-5 = 200

Other way:

d (n) = d (n-1) x (-5) = > d (n) = d (1) x (-5) ^ (n-1)

d (3) = d (1) x5^ (3-1) = 8x5^2=8x25 = 200