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11 August, 07:30

a) In how many ways can 6 people be lined up to get on a bus? (b) If 4 specific persons, among 6 , insist on following each other, how many ways are possible? (c) If 2 specific persons, among 6 , refuse to follow each other, how many ways are possible?

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  1. 11 August, 07:44
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    Answer: a) 720

    b) 144

    c) 480

    Step-by-step explanation:

    a) 6 people changing places in a line is permutation (because the a line has a order)

    This way, 6 people in a line is 6! = 6.5.4.3.2.1 = 720

    b) We can consider 4 people a block that will permut, so, instead of 6 people we have 3 [a block of 4 people and 2 more):

    3! = 3.2.1 = 6

    This group of 4 can also permut, so 4! = 4.3.2.1 = 24

    Total = 3!.4! = 6.24=144

    c) For this case, the easiest way is doing the complement. Calculate how many the 2 people are together and subtract from the total, so:

    We can consider 2 people a block that will permut, so, instead of 6 people we have 5 [a block of 2 people and 4 more):

    5! = 5.4.3.2.1 = 120

    The 2 people from the block will permut as well:

    2! = 2.1 = 2

    Total: 5!.2! = 120.2 = 240.

    For the case they are not following each other:

    720 - 240 = 480
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