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12 November, 17:25

the first term of an arithmetic sequence is 4 and the tenth term is 10. how can you find the sixth term of the sequence.

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  1. 12 November, 17:47
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    Step-by-step explanation:

    Let 1st term be (a) and common difference between sequence be (d). then according to question:

    a=4

    a+9d=10

    i. e 4+9d=10

    or, 9d=10 - 4

    or, d = 6:9

    Hence, d=2/3

    Now,

    As, sixth term = a+5d

    =4+5 (2/3)

    =4 + (10/3)

    = (12+10) : 3

    =22:3

    =22/3

    Thus, the required sixth term is 22/3.
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