Prove the trigonometric identity:

(csc^2x) / (cotx) = cscxsecx ... ?

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Mathematics

5 October, 13:10

Prove the trigonometric identity:

(csc^2x) / (cotx) = cscxsecx ... ?

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Aniyah Mccormick · Answer 1

Cscx = 1 / sinx, so csc^2x = 1 / sin²x, and cotx=cosx / sinx

so (csc^2x) / (cotx) = (1 / sin²x) (sinx/cosx) = 1 / (sinxcosx) = 1/sinx 1/cosx

finally

(csc^2x) / (cotx) = cscxsecx

Prove the trigonometric identity:(csc^2x) / (cotx) = cscxsecx ... ?

Prove the trigonometric identity:

(csc^2x) / (cotx) = cscxsecx ... ?