What values of b satisfy 3 (2b + 3) 2 = 36? b = and b = and b = and b = and

Answer: The correct answer is (3*2b) + (3*3) (2) = 36

6b + (9) (2) = 36

6b+18=36

6b=36-18

6b=18

b=3.

3 (2b + 3) 2 = 36

Steps

First, divide both sides by 6

3 (2b + 3) * 2/6 = 36/6

Simplify,

2b + 3 = 6

Then, subtract 4 from both sides

2b + 3 - 3 = 6 - 3

Simplify,

2b = 3

Then, divide both sides by 2

2b/2 = 3/2

Simplify,

b = 3/2