What are the zeros of the quadraic function?

f (x) = 2x^2 + 10x - 12

The zeros are 1 and - 6

Step-by-step explanation:

f (x) = 2x^2 + 10x - 12

Set the equation equal to zero

0 = 2x^2 + 10x - 12

Divide each side by 2

0/2=2/2x^2 + 10/2x - 12/2

0 = x^2 + 5x - 6

Factor

What 2 numbers multiply to - 6 and add to 5

6*-1 = - 6

6-1 = 5

(x+6) (x-1) = 0

Using the zero product property

x+6 = 0 x-1=0

x=-6 x=1