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Derek Dean
Mathematics
20 April, 14:56
How do you solve 6-√x-1 = 1?
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Sidney Stone
20 April, 15:00
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6-√x-1 = 1;
x>=0;
then, √x = 5-1 √x = 4 x = 16 and, 16 >=0;
the solution is: 16;
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Broderick Schmidt
20 April, 15:13
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6-√x-1 = 1
6-1 = √x-1
5 = √x-1
square both sides,
25=x-1
25+1=x
26=x
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