A businessman was comparing his company's profits for two consecutive months. In November, n, were 0.04 thousand dollars more than in December, d. The two months had a combined income of 3.15 thousand dollars. Which system of equations could be used to determine the amount of profit for each month, in thousands of dollars?

A) n+d = 3.15

n+0.04=d

B) n-3.15=d

d+0.04=n

C) d-3.15=n

n+0.04=n

D) n+d=3.15

d=0.04=n

Question

Jarrett Norris

Mathematics

2 July, 03:14

A businessman was comparing his company's profits for two consecutive months. In November, n, were 0.04 thousand dollars more than in December, d. The two months had a combined income of 3.15 thousand dollars. Which system of equations could be used to determine the amount of profit for each month, in thousands of dollars?

A) n+d = 3.15

n+0.04=d

B) n-3.15=d

d+0.04=n

C) d-3.15=n

n+0.04=n

D) n+d=3.15

d=0.04=n

+3

Answers (1)

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Gibbs · Answer 1

N and d are both numbers of thousands of dollars.

Thus, if n = 1, that means $1000.

Here n = d + 0.4.

Note that in C, n+0.04=n is completely wrong.

Similarly, in D, d = 0.04 = n is completely wrong.

The "combined profit amount" for Nov. and Dec. is n + d = 3.15.

Only A matches this info. Your answer is A.