There are currently 19 frogs in a (large pond. the frog population grows exponentially, tripling every 8 days. how long will it take (in days for there to be 290 frogs in the pond?

Population growth factor = 3^ (days/8)

Day zero 19 Frogs

Population = 19*3^ (days / 8)

We are to calculate when population = 290

290 = 19*3^ (days / 8)

290 / 19 = 3^ (days/8)

log (290/19) = (days/8) * log (3)

log (15.2631578947) / log (3) = days/8

1.1836443969 / 0.4771212547 = days/8

2.4808041672 = days / 8

days = 8 * 2.4808041672

days = 19.8464333372 days