A ball is thrown in the air and it's height in feet, at any time, in seconds, is represented by the equation (h (t) = - 4^2+16) when is the ball higher than 12 feet of the ground

Question

Jacey Petersen

Mathematics

15 November, 01:15

A ball is thrown in the air and it's height in feet, at any time, in seconds, is represented by the equation (h (t) = - 4^2+16) when is the ball higher than 12 feet of the ground

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Theodore Key · Answer 1

To determine the time when the ball would be higher than 12 feet off the ground, we use the equation given which relates time and the height. It is given as:

h (t) = - 4t^2 + 16

By substituting 12 to the height, we solve for the value of t.

h (t) = - 4t^2 + 16

12 = - 4t^2 + 16

-4 = - 4t^2

t = 0 s

Therefore, the ball would never reach a height of 12 feet or higher than that or it can represent that the ball is thrown at a height of 12 feet so any time greater than 0 the ball is higher than 12 feet.