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25 January, 17:56

People arrive at a college admissions office at rate 1 per minute, and the arrival is a Poisson process. When k people have arrive, a tour starts. Student tour guides are paid $20 for each tour they conduct. The college estimates that it loses ten cents in good will for each minute a person waits. What tour group (not counting the guide) minimizes the average cost per person?

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  1. 25 January, 18:24
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    K=20

    Step-by-step explanation:

    There seem to be no randomness in the question.

    At 1 per minutes the arrival rate is fixed.

    Then compute the average cost for each person to give a four, adding the cost of guide and time waiting cost ...

    Therefore, K is the number of people hoping will show up.

    Number of per minute waiting

    = 1/2 (K-1) K.

    Tour cost 20+1/20 (K-1).

    Cost per guest = 20/k + 1/20 (K-1)

    If the derivative is set to Zero

    K=20
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