A 5.00 L air sample has a pressure of 107 kPa at a temperature of - 50C. If the temperature is raised to 102C and the volume expands to 7.00L, what will the new pressure be?

129.9 kPa

Step-by-step explanation:

The relationship between temperature T, volume V and pressure P is given by the ideal gas equation which is given as

K = PV/T where K is a constant such that were there is a change of temperature T₁, volume V₁ and pressure P₁ to temperature T₂, volume V₂ and pressure P₂ then the relationship may be given

P₁V₁/T₁ = P₂V₂/T₂

where T is measured in ⁰K

T₁ = - 50 + 273

= 223 ⁰K

T₂ = 102 + 273

= 379 ⁰K

5 * 107/223 = P₂ * 7/379

P₂ = 129.9 kPa