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22 April, 17:08

Curtis build a dog house with base shaped like a cube and a roof shaped like a pyramid. The cube has an edge lenght of 3 1/2 feet. The height of the pyramid is 5 feet. Find the volume of the doghouse rounded to the nearest tenth.

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  1. 22 April, 17:19
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    The volume of the cube is:

    V1 = L ^ 3

    Where,

    L: length of the sides of the cube.

    Substituting we have:

    V1 = (3 + 1/2) ^ 3

    V1 = 42,875 feet ^ 3

    The volume of the pyramid is:

    V2 = ((Ab) * (h)) / (3)

    Where,

    Ab: base area

    h: height

    Substituting we have:

    V2 = (((3 1/2) * (3 1/2)) * (5)) / (3)

    V2 = 20.41666667 feet ^ 3

    The volume of the house is the sum of both volumes:

    V1 + V2 = 42,875 feet ^ 3 + 20.41666667 feet ^ 3

    V1 + V2 = 63.29166667 feet ^ 3

    Nearest tenth:

    V1 + V2 = 63.3 feet ^ 3

    Answer:

    The volume of the doghouse rounded to the nearest tenth is:

    V1 + V2 = 63.3 feet ^ 3
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