Mason and Nora decided to swim across the river. Mason began swimming 1 minute earlier than Nora.

Mason swam at a speed of 6 feet per second.

Nora swam at a speed of 8 feet per second.

For how many seconds had Mason been swimming at the moment when the two swimmers had swam exactly the same distance?

Question

Hannah Preston

Mathematics

10 March, 14:57

Mason and Nora decided to swim across the river. Mason began swimming 1 minute earlier than Nora.

Mason swam at a speed of 6 feet per second.

Nora swam at a speed of 8 feet per second.

For how many seconds had Mason been swimming at the moment when the two swimmers had swam exactly the same distance?

+2

Answers (1)

Know the Answer?

Stephanie Maldonado · Answer 1

Mason:

time = t

V = 6 ft/s

Distance = v * t = 6t

Nora:

time = t - 60 [ I passed 1 minute to seconds]

V = 8 ft/s

Dsitance = v*t = 8 (t - 60)

Both distance are equal

6t = 8 (t-60)

6t = 8t - 480

8t - 6t = 480

2t = 480

t = 480/2

t = 240 s

Mason had been swimming for 240 seconds when both had swan the same distance.

Mason and Nora decided to swim across the river. Mason began swimming 1 minute earlier than Nora.Mason swam at a speed of 6 feet per second.Nora swam at a speed of 8 feet per second.For how many seconds had Mason been swimming at the moment when the two swimmers had swam exactly the same distance?