Tim wants to build a rectangular fence around his yard. He has 42

feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.

A) 4w+4=42; l=18

B) 4w+8=42; l=16

C) 6w-42; l=7

D) 6w=42; l=14

Question

Yuliana Chung

Mathematics

16 February, 17:15

Tim wants to build a rectangular fence around his yard. He has 42

feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.

A) 4w+4=42; l=18

B) 4w+8=42; l=16

C) 6w-42; l=7

D) 6w=42; l=14

+5

Answers (2)

Know the Answer?

Jewel Padilla · Answer 1

D) 6w = 42; l=14

Step-by-step explanation:

since we know,

perimeter of a rectangle = 2 (length + width)

therefore,

=> 2 (l + w) = 42

but we know, l = 2w

=> 2 (3w) = 42

=> 6w = 42,

Konnor Carpenter · Answer 2

I think its D

Tim wants to build a rectangular fence around his yard. He has 42feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.A) 4w+4=42; l=18B) 4w+8=42; l=16C) 6w-42; l=7D) 6w=42; l=14

Tim wants to build a rectangular fence around his yard. He has 42

feet of fencing. If he wants the length to be twice the width, what is the largest possible length? Write an equation and solve.

A) 4w+4=42; l=18

B) 4w+8=42; l=16

C) 6w-42; l=7

D) 6w=42; l=14