As a certain engine's rotation speed increases, its temperature increases at a constant rate.

The table compares the engine's rotation speed (in cycles per second) and its temperature (in degrees Celsius).

Rotation (cycles per second) : 11, 13, and 15.

Temperature (degrees Celsius) : 23.8, 25.4, and 27.

What is the increase in temperature that comes with an increase of 1 cycle per second in the rotation?

0.8

Step-by-step explanation:

Since the temperature increased at a constant rate, the table describes a linear relationship.

Moreover, the increase in temperature that comes with an increase of 1 cycle per second in the rotation corresponds to the rate of change of the relationship.

The table of values shows that for each increase of in Rotation, Temperature increases by 1.6 degrees Celsius. The rate of change is the ratio of those corresponding differences.

ΔRotation = 1.6

ΔTemperature = 2

1.6/2=0.8

In conclusion, the increase in temperature that comes with an increase of 1 cycle per second in the rotation is 0.8 degrees Celsius.

The answer is 15