Given ABCD is a parallelogram ABE equals 180° CBE is congruent to CEB prove DAE is congruent to CEA

The proved is given below.

Step-by-step explanation:

Given ABCD is a parallelogram and also ∠ABE equals 180°, ∠CBE ≅ ∠CEB

We have to prove that ∠DAE ≅ ∠CEA

As ∠CEA=∠CBE → (1)

and given ABCD is a parallelogram implies AD||CB

∴ ∠DAE=∠CBE → (2) as these are corresponding angles.

From equation (1) and (2), we get

∠DAE=∠CEA

Hence, ∠DAE is congruent to ∠CEA

Hence Proved