How can i solve this 4 (3x-1) = 3+8x-11

Question

Alexis Swanson

Mathematics

21 June, 06:33

How can i solve this 4 (3x-1) = 3+8x-11

+4

Answers (2)

Know the Answer?

Linnea · Answer 1

12x-4=3+8x-11

4x=-4

x=-1

Velez · Answer 2

4 (3x-1) = 3+8x-11

Simplify

4 (3x-1) = 3+8x-11

(4) (3x) + (4) (-1) = 3+8x+-11 (Distribute)

12x+-4=3+8x+-11

12x-4 = (8x) + (3+-11) (Combine Like Terms)

12x-4=8x+-8

12x-4=8x-8

Subtract 8x from both sides.

12x-4-8x=8x-8-8x

4x-4=-8

Add 4 to both sides.

4x-4+4=-8+4

4x=-4

Divide both sides by 4.

4x/4=-4/4

x=-1