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Paul Bender
Mathematics
4 February, 11:17
P (-3) = x^3+5; evaluate P (-3)
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Guy
4 February, 11:29
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You are given P (x) = x^3 + 5, not P (-3). You are to evaluate the function at x=-3.
The function is P (x) = x^3+5. Let's now replace x with (-3):
P (-3) = (-3) ^3 + 5 = - 27 + 5 = - 22 (answer)
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