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21 May, 11:17

1 find the least number between 200 and 500 which leaves a reminder of 3 in each case when devided by 8,10,12 and 30

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  1. 21 May, 11:24
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    X:8=c1 reminder 3

    x=M₈ + 3

    x:10=c2 reminder 3

    x=M₁₀ + 3

    x:12=c3 reminder 3

    x=M₁₂ + 3

    x:30=c4 reminder 3

    x=M₃₀ + 3

    x=[M₈; M₁₀; M₁₂; M₃₀]+3

    8=2³

    10=2 * 5

    12=2² * 3

    30=2*3 * 5

    200 < x < 500

    x = 2³ * 5 * 3 + 3

    x=8*5*3+3

    x=120+3

    x=123 it doesn't corespond

    x=2⁴ * 15+3

    x=16*15+3

    x=240+3

    x=243

    x=8*5*9+3

    x=40*9+3

    x=360+3

    x=363

    x=8*5*3*4+3

    x=40*12+3

    x=480+3

    x=483

    x=8*5² * 3+3

    x=24*25+3

    x=600+3

    x=603 it doesn't corespond

    x={243; 363; 483}
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