A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 90 gallons of a mixture that contains 90% pure antifreeze, how many gallons of each brand of antifreeze must be used?

Question

Roland White

Mathematics

19 July, 13:04

A chemical company makes two brands of antifreeze. The first brand is 65% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 90 gallons of a mixture that contains 90% pure antifreeze, how many gallons of each brand of antifreeze must be used?

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Answers (1)

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Colt Hobbs · Answer 1

Let us represent the gallons of 65% antifreeze as x. If the total volume is 90 gallons, then the amount of 95% antifreeze can be written as (90 - x). Then we add up the total amount of antifreeze based on the volumes and percentages:

(0.65) x + (0.95) (90 - x) = (0.90) (90)

0.65x + 85.5 - 0.95x = 81

-0.3x = - 4.5

x = 15

90 - x = 75

Therefore, 15 gallons of 65% antifreeze and 75 gallons of 95% antifreeze were used.