The sum of twice a number and five is greater than three times the number minus three

Rememember you can do anything to an equation as long as you do it to boht sides except diviede by zero and when you mulitply by a negative with inequalities (<, <,>,>) remember to flip the sign

sum means add

twice a number means a number times 2 (represented by x)

greater than means >

3 times means multiply

minus is minus

so

sum of twice a number and 5 (2x+5) is greater than (>) 3 times the number (3x) minus 3 (-3)

we now have

2x+5>3x-3

subtract 2x from both sides

5>x-3

add 3 to both sides

8>x

x<8

therefor x is any number less than 8

x can be 7,6,5,4,3,2,1,0,-123189030, π

basically x<8

First, write out the problem. 2x + 5 > 3x - 3

next, solve.

2x + 5 > 3x - 3

add 3 to the left side.

2x + 8 > 3x

subtract 2x from the right side.

8 > 1x