The perimeter of a rectangle is 50 meters. The width is five more than the length. Find the dimensions.

Question

Cecilia Hunter

Mathematics

23 April, 06:09

The perimeter of a rectangle is 50 meters. The width is five more than the length. Find the dimensions.

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Answers (1)

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Jeffrey Lee · Answer 1

P = 2L + 2 W = 50 P=50

W = L + 5 Plug into equation (substitution)

2L + 2 L+5 = 50

4L=50 - 5

L = 45/4

L=11.25

P = 2 L + (2 L + 5) = 50

P = 2 (11.25) + 2 (11.25) + 5 = 50

P=22.5 + 27.5

P=50 2L=22.5 and 2W = 27.5

L=11.25 W = 13.75