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24 August, 01:30

The riverside geyser in Yellowstone erupts about every 6.25 h. When the geyser erupts, the water has an initial upward velocity of 69 ft / s. What is maximum height of the geyser?

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  1. 24 August, 01:58
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    Correct answer: Hmax = 22.11 m

    Step-by-step explanation:

    The subject of this problem is a vertical shot upwards, to which the following formula applies:

    V₀² - V² = 2 · g · H where is:

    V₀ - initial velocity

    V - final velocity

    g = 10 m/s²

    H - final height

    Given:

    V₀ = 69 ft/s = 21.03 m/s

    V = 0 m/s

    Hmax = ?

    V₀² = 2 · g · Hmax ⇒ Hmax = V₀² / 2 · g

    Hmax = 21.03² / 2 · 10 = 442.26 / 20 = 22.11 m

    Hmax = 22.11 m

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