Two crocodile owners (owner i and owner ii) were talking and, during the conversation, they realised a weird coincidence. if owner i sold 7 of his crocodile to owner ii, owner i would have the same amount of crocodiles as owner ii. on the other side, if owner ii sold 7 of his crocodiles to owner i, owner i would have exactly the double of crocodiles of owner ii. how many crocodiles each of them have?

Question

Kendrick Leon

Mathematics

2 June, 19:40

Two crocodile owners (owner i and owner ii) were talking and, during the conversation, they realised a weird coincidence. if owner i sold 7 of his crocodile to owner ii, owner i would have the same amount of crocodiles as owner ii. on the other side, if owner ii sold 7 of his crocodiles to owner i, owner i would have exactly the double of crocodiles of owner ii. how many crocodiles each of them have?

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Answers (1)

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Lorelei Camacho · Answer 1

Let owner 1 have x crocodiles and owner 2 have y crocodiles, then we can set up 2 equations:-

x - 7 = y + 7 (when owner 1 sells 7 to owner 2)

x + 7 = 2 (y - 7) (when owner 2 sells 7 to owner 1)

from first equation

x - y = 14 and from second equation:_

-x + 2y = 21 Adding thes 2 equations:-

y = 35

and therefore x = 14 + 35 = 49

So owner 1 has 49 crocs and owner 2 has 35 crocs.