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7 July, 05:52

How much does the sum of the roots of the equation (x+1) (x-3) = 0 exceed the product of its roots? (a) 1 (b) 2 (c) 3 (d) 4 (e) 5?

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  1. 7 July, 06:10
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    (x+1) (x-3) = 0

    (x+1) = 0, (x-3) = 0

    x=-1, x=3 are the roots of the equation

    so, the sum the roots of the equation: - 1+3=2

    then the product of the roots of the equation: - 1*3=-3

    so, 2 - (-3) = 2+3=5

    it exceeds by 5

    so the answer is (e) 5
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