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8 April, 03:29

Find two consecutive positive integers such that the sum of their squares is 145

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  1. 8 April, 03:57
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    8,9

    Step-by-step explanation:

    (x) ^2 + (x+1) ^2=145

    x²+x²+2x+1=145

    2x²+2x+1-145=0

    x²+x-72=0

    x²+9x-8x-72=0

    x (x+9) - 8 (x+9) = 0

    (x+9) (x-8) = 0

    x=-9 (rejected being negative)

    x=8

    x+1=8+1=9
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