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29 August, 08:21

Find the perimeter of a square with an area of 702.25

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  1. 29 August, 08:35
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    area of a square = 702.25

    A = side square

    let's take side of a square = a

    therefore,

    702.25 = a^2

    a = √702.25 = 26.5

    perimeter (P) of a square = 4a

    P = 4x 26.5 = 106

    so perimeter of a square is 106
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