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11 May, 12:24

What radius of a circle is required to inscribe an equilateral triangle with an area of 15.588 in2 and an altitude of 5.196 in? (round to nearest tenth)

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  1. 11 May, 12:45
    0
    Area of triangle = 1/2 base x height

    15.588 = 1/2 * base x 5.196

    15.588 = base x 2.598

    base = 15.588 / 2.598 = 6

    equi center of triangle = 1/3*5.196 = 1.732

    radius of circle = Sqrt (1.732^2 + 3^2) =

    sqrt (2.999824 + 9) =

    sqrt (11.999824) = 3.464

    rounded to nearest tenth = 3.5 inches
  2. 11 May, 12:50
    0
    Round it to the nearest tenth so that would be 3.5
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