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Tiana
Mathematics
7 January, 10:43
Factor using a GCF:
16xy2+28xy+8y
+2
Answers (
1
)
Joaquin Shepard
7 January, 11:04
0
4y (4xy + 7x + 2)
Step-by-step explanation:
16xy^2+28xy+8y
16xy^2 = 2*2*2*2*x*y*y
28xy = 2*2*7 * x*y
8y = 2*2*2*y
The common factors are 2*2*y = 4y
2*2*2*2*x*y*y + 2*2*7 * x*y+2*2*2*y
2*2*y (2*2*x*y + 7 * x+2)
4y (4xy + 7x + 2)
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