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15 October, 08:28

Fill in the steps to solve the log log base x of (2x) ^3=6

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  1. 15 October, 08:33
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    x=2

    Step-by-step explanation:

    logx (2x) ^3 = 6

    We can rewrite without the exponent

    3 logx (2x) = 6

    Divide by 3

    3/3 logx (2x) = 6/3

    logx (2x) = 2

    Raise each side to the base x

    x^ logx (2x) = x^ 2

    2x = x^2

    Subtract 2x from each side

    2x-2x = x^2 - 2x

    0 = x^2 - 2x

    Factor an x

    0 = x (x-2)

    Using the zero product property

    x = 0 x-2 = 0

    x = 0 x=2

    We cannot have a base of 0, so x cannot equal 0

    x=2
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