What is the coordinates of the vertex of y=x^2-4x+1

By the method : Completing the square

x²-4x+1=0

x²-4x+1-1=-1

x²-4x = - 1

x²-4x+4 = - 1+4

(x-2) ² = 3

(x-2) ²-3=0

x (vertex)

x-2=0

x=2

y (vertex) = - 3

S = (2, - 3)

So to find the x vertex u have to apply the formula x = - b/2a so it will be

x = - (-4) / 2 (1)

x = 4/2

x = 2

and to find the y vertex u just substitute the x value into the original equation so it will be

y = (2) ^2-4 (2) + 1

y = 4-8+1

y = - 3

so the coordinates of the vertex are (2,-3)