Given that f (1) = 2 and f' (1) = 4, find the derivative of f (x) loge (x) when x=1

2

Step-by-step explanation:

loge (x) is ln (x)

f (x) * ln (x)

Differentiate using product law

[ln (x) * f' (x) ] + [ (1/x) * f (x) ]

x = 1

[ln (1) * f' (1) ] + [ (1/1) * f (1) ]

(0 * 4) + (1 * 2)

0 + 2

2