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16 September, 07:12

Given that f (1) = 2 and f' (1) = 4, find the derivative of f (x) loge (x) when x=1

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  1. 16 September, 07:33
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    Step-by-step explanation:

    loge (x) is ln (x)

    f (x) * ln (x)

    Differentiate using product law

    [ln (x) * f' (x) ] + [ (1/x) * f (x) ]

    x = 1

    [ln (1) * f' (1) ] + [ (1/1) * f (1) ]

    (0 * 4) + (1 * 2)

    0 + 2

    2
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