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13 December, 10:35

X^4-10x^2+21=0 factor using quadratic techniques

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  1. 13 December, 10:41
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    (x - sqrt (7)) (x + sqrt (7)) (x - sqrt (3)) (x + sqrt (3))

    Step-by-step explanation:

    x⁴ - 10x² + 21 = 0

    Let t = x²

    Then the equation becomes,

    t² - 10t + 21 = 0

    t² - 7t - 3t + 21 = 0

    t (t - 7) - 3 (t - 7l

    (t - 7) (t - 3)

    Since t = x²,

    (x² - 7) (x² - 3)

    Using a² - b² = (a - b) (a + b)

    (x - sqrt (7)) (x + sqrt (7)) (x - sqrt (3)) (x + sqrt (3))

    sqrt : square root

    x = + / - sqrt (7) & + / - sqrt (3)
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