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2 September, 22:49

A right cylindrical container perfectly holds 5 tennis balls placed one above the other. The radius of each ball is 3.35 centimeters. What is the approximate volume of the unoccupied space in the container?

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  1. 2 September, 23:01
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    Answer = Cylinder Volume - 5 (1 of the ball's volume)

    Cylinder Volume: (pi) (r^2) (h)

    Sphere Volume: 4/3 (pi) (r^3)

    Total of the Tennis balls' volume = 787.4

    Total Volume of Cylinder = 590.55

    I think 196.85 is the space left? I might've made an error ...
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